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JHS5× 10 waterproof cable JHS submersible pump national standard cable price

NegotiableUpdate on 05/12
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Overview

JHS5 10 waterproof cable JHS submersible pump national standard cable price $r $n for connecting AC voltage 300/500V and below front water motor, waterproof rubber sleeve cable with one end in water, long-term allowable working temperature not exceeding 65 ℃

Product Details

JHS5 × 10 waterproof cable JHS submersible pump national standard cable price

JHS 300/500VWaterproof rubber sheathed cables for submersible motors and below4610

162535

507095 1The3

4 TL/Q 13-91Connect AC voltage300/500VFor front water motors and below, one end of the waterproof rubber sheathed cable is submerged in water, and the long-term allowable working temperature does not exceed65℃

JHSBFlat waterproof rubber sheathed cable for submersible motors1625

35The50 3 TL/J 13-91Suitable for transmitting electricity through water and electricity pumps before drainage, with a long-term allowable working temperature not exceeding85℃

JHSWaterproof rubber sheathed cable for AC voltage supply500VTransmission of electrical energy on submersible motors up to and including. Under long-term immersion and high water pressure, it has good electrical insulation performance.

JHS5 × 10 waterproof cable JHS submersible pump national standard cable price

model

name

Cross section mm2

core count

execution standard

main purpose

JHS

300/500VWaterproof rubber sheathed cables for submersible motors and below

4610
162535
507095

1The3
4

TL/Q 13-91

Connect AC voltage 300/500VFor front water motors and below, one end of the waterproof rubber sheathed cable is submerged in water, and the long-term allowable working temperature does not exceed65

JHSB

Flat waterproof rubber sheathed cable for submersible motors

1625
35The50

3

TL/J 13-91

Suitable for transmitting electricity through water and electricity pumps before drainage, with a long-term allowable working temperature not exceeding 85 ° C

Copper weight X copper price calculation:

Wire diameter ÷ 2=1.25X1.25X3.14

=Square number X number of wires X0.89X copper price+10% processing fee at that time.

Formula for calculating the cost price of rubber sheathed cables

Square X1.83=weight of copper X current copper price+price of rubber (weight X 0.4 yuan/jin)=cost price+10% processing fee

The price of cables=manufacturing material cost+fixed expenses+taxes+business expenses+profit

Manufacturing material cost=Material cost * (1+Material consumption) (Material cost is the theoretically calculated value)

Fixed costs vary depending on the situation of each company, generally including production wages, management wages, utilities, repair costs, depreciation costs, rent, and transportation costs

Calculation formula for current carrying capacity

Estimation mnemonic

Multiply 2.5 by 9 and subtract one from the top to follow the order.

Thirty five times three and a half, in pairs, subtract five points.

Conditions are subject to change and conversion, with high temperature copper upgraded at a 10% discount.

The number of pipes passing through is 2-34, with a full load flow of 876.

Explanation:

The mnemonic in this section does not directly indicate the current carrying capacity (safe current) of various insulated wires (rubber and plastic insulated wires), but rather represents it by multiplying the cross-section by a certain multiple, obtained through mental calculation. From Table 5.3, it can be seen that the multiplier decreases with the increase of the cross-section.

Multiply 2.5 by 9, subtract one from the top and follow the order

The phrase 'Multiply 2.5 by 9 and subtract one from the top in order' refers to aluminum core insulated wires with various cross-sections of 2.5mm 'and below, whose current carrying capacity is approximately 9 times the number of cross-sections. For a 2.5mm 'wire, the current carrying capacity is 2.5 × 9=22.5 (A). The multiple relationship between the current carrying capacity and the number of cross-sections of wires with a diameter of 4mm 'and above is arranged in ascending order according to the wire number, and the multiple is gradually reduced by l, that is, 4 × 8, 6 × 7, 10 × 6, 16 × 5, and 25 × 4.

Thirty five times three and a half, in pairs, subtract five points.

The current carrying capacity of a 35mm conductor is 3.5 times the number of cross-sections, that is, 35 × 3.5=122.5 (A). The multiple relationship between the current carrying capacity and the number of cross-sections of wires with a diameter of 50mm 'and above is changed to two wire numbers grouped together, and the multiples are sequentially reduced by 0.5. The current carrying capacity of 50 and 70mm 'wires is three times the number of cross-sections; The current carrying capacity of wires 95 and 120mm is 2.5 times their cross-sectional area, and so on.

Conditions are subject to change and conversion, with high temperature copper upgraded at a 10% discount.

Conditions are subject to change and conversion, with high temperature copper upgraded at a 10% discount. The above mnemonic is determined for aluminum core insulated wire and exposed to an ambient temperature of 25 ℃. If the aluminum core insulated wire is laid openly in an area where the ambient temperature is higher than 25 ℃ for a long time, the current carrying capacity of the wire can be calculated according to the above formula, and then discounted by 10%; When using copper core insulated wire instead of aluminum wire, its current carrying capacity is slightly larger than that of aluminum wire of the same specification. The current carrying capacity that is one wire size larger than aluminum wire can be calculated using the above formula. The current carrying capacity of 16mm copper wire can be calculated based on 25mm2 aluminum wire.

The number of pipes passing through is 2-34, with a full load flow of 876.

When two, three, or four wires are laid through a conduit, their current carrying capacities are 80%, 70%, and 60% of the calculated current carrying capacity (single laying), respectively.